Q. 12

# The moment of inertia of a uniform rod of mass 0.50 kg and length 1 m is 0.10 kg-m^{2} about a line perpendicular to the rod. Find the distance of this line from the middle point of the rod.

Answer :

Given-

Length of the rod = 1 m,

Mass of the rod = 0.5 kg

Let at a distance x from the center the rod is moving

Applying parallel axis theorem –

Where

r is the distance between the parallel axes.

Applying the parallel axes theorem, the moment of inertial about the point d becomes-

Substituting the values -

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Figure 5.9 shows (v_{x} ,t ),and( (v_{y} ,t) diagrams for a body of unit mass. Find the force as a function of time.

Physics - Exemplar

The door of an Amirah is 6 ft. high, 1.5 ft. wide and weighs 8 kg. The door is supported by two hinges situated at a distance of 1 ft. from the ends. If the magnitudes of the forces exerted by the hinges on the door are equal, find this magnitude.

HC Verma - Concepts of Physics Part 1Consider the following two equations

(A)

(B)

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HC Verma - Concepts of Physics Part 1