Answer :

The plot of molar conductivity (λ_{m}) vs different C^{1/2} values of KCL solutions given is a straight line.

• and from the equation

λ_{m} = λ^{0}_{m} – A C^{1/2} we can see that the intercept for the straight line( where C^{1/2} = 0 ) is actually the limiting molar conductivity λ^{0}_{m} (from the concept of y=mx + c, where c=the intercept )

the value of which can be determinedfrom the graph and is = 150.00 S Cm^{2} mol^{-1}

• on the other hand, the slope of the graph is the value of A which can be determined by the concept y=mx + c, where m is the slope and

m=(y – c)/x,

• by taking the molar conductivity λ_{m} =147.2 for the C^{1/2} = .034 from the graph,

A= - slope =

= - 82.35 S cm^{2} mol^{–1}(mol/L^{–1})-^{1/2}.

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