Q. 16

The masses of 11C and 11B are respectively 11.0114 u and 11.0093 u. Find the maximum energy a positron can have in the β+-decay of 11C to 11B

Answer :



The maximum energy for the positron will be equal to the energy due to the mass defect (ΔM)


ΔM = [11.0114-11.0093] ×931 MeV


= 1.955 MeV


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