The magnetic inte

Given:

Current in the solenoid I=2A

Magnetic intensity H at the centre =1500Am^-1

We know that ,

Magnetic field produced by solenoid at the centre (B) is given by

(i)

Where,

n=no. of turns per unit length

I=current in the solenoid

μ₀=absolute permeability of vacuum

also magnetizing field intensity (H) in the absence of any material is given by

Where

B=net magnetic field

Putting the value of eqn.(i)

Putting the values of H and I we get

turns/m

turns/cm

Therefore no. of turns per cm of the solenoid is 7.5 turn/cm