Answer :

Given:


Current in the solenoid I=2A


Magnetic intensity H at the centre =1500Am-1


We know that ,


Magnetic field produced by solenoid at the centre (B) is given by


(i)


Where,


n=no. of turns per unit length


I=current in the solenoid


μ0=absolute permeability of vacuum


also magnetizing field intensity (H) in the absence of any material is given by



Where


B=net magnetic field


Putting the value of eqn.(i)



Putting the values of H and I we get



turns/m


turns/cm


Therefore no. of turns per cm of the solenoid is 7.5 turn/cm


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

The permanent magHC Verma - Concepts of Physics Part 2

The permanent magHC Verma - Concepts of Physics Part 2

Pick the correct HC Verma - Concepts of Physics Part 2

Which of the follHC Verma - Concepts of Physics Part 2

A paramagnetic maHC Verma - Concepts of Physics Part 2

A rod when suspenHC Verma - Concepts of Physics Part 2

Do permeability aHC Verma - Concepts of Physics Part 2

To keep valuable HC Verma - Concepts of Physics Part 2

A paramagnetic maHC Verma - Concepts of Physics Part 2

A ferromagnetic mHC Verma - Concepts of Physics Part 2