Answer :

Given:


No. of turns/cm=50


Magnetic field inside without iron core=2.5× 10-3T


Magnetic field inside solenoid with iron core=2.5T


Cross-sectional area of solenoid=4cm2


We know that magnetic field(B) inside the solenoid without iron core is given by



Where,


n=no. of turns in a given length


I=current through solenoid


Putting the values of B, I and μ0



A


Therefore, current through the solenoid is given by 0.4A


Magnetization I of the core is given by formula



Where H=magnetization intensity



Let the magnetic field with iron core and without iron is given by B2 and B1 respectively.


Then,





Putting the values of B1,B2 and μ


Am-1



Therefore, the magnetization in the core is 2× 106A/m


Intensity of magnetization is given by the formula



Where,


M=magnetic moment given by the formula


…(i)


Where,


m=magnetic pole strength


l=length between two poles


also volume inside solenoid is given by


..(ii)


Using eqns.(i) and (ii) we get



Putting the values of I and A



A-m


A-m


Therefore, magnetic pole strength developed inside the core is given by 800A-m


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