Answer :

The magnetic field energy in an inductor is given by … (i), where L = inductor, i = current.


The graph of alternating current is given by:



From (i), we can see that the magnetic field energy reached its maximum and minimum value when the current is maximum and 0 respectively.


Also, from the graph we can see that the time taken by the current to change from its maximum to zero value is T/4, where T = time period.


Now, from the given problem, = 5 ms = 0.005 s


Hence, time period T = (0.005 x 4) s = 0.02 s


Therefore, frequency of oscillation is equal to = = 50 Hz. (Ans)

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