Q. 5

The length and br A. 164 ± 3 cm2

B. 163.62 ± 2.6 cm2

C. 163.6 ± 2.6 cm2

D. 163.62 ± 3 cm2

Answer :

(i)In multiplication the answer is rounded off to the same number of significant figures as possessed by the least precise term used in the calculation.


(ii)The final result must contain as many significant figures as are in the original number with the least significant figures.





No. of significant figures in 16.2 is 3 and in 10.1 is 3. Here both are the least precise terms used. Therefore, the answer must contain 3 significant figures.


So, rounding off the answer to 3 significant figures we get



Now error,


If is the error in the area, be the error in length and be the error in breadth, then relative error is calculated as .


(For the formula part refer to


NCERT class 11 part 1 unit


and measurement chapter)




In dimensional analysis, in multiplication the answer is rounded off to the same number of significant figures as possessed by the least precise term used in the calculation. Here 0.1 has least precision and has 1 significant figure. Therefore,


(By rounding off to one significant figure)


Area,

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Time for 20 oscilPhysics - Exemplar

The radius of a cHC Verma - Concepts of Physics Part 1

Express unified aPhysics - Exemplar

Measure of two quPhysics - Exemplar

The Vernier scalePhysics - Exemplar

The length and brPhysics - Exemplar

The numbers 2.745Physics - Exemplar

Which of the follPhysics - Exemplar

You measure two qPhysics - Exemplar