Q. 14

The internal energy of a gas is given by U = 1.5 pV. It expands from 100 cm3 to 200 cm3 against a constant pressure of 1.0 × 105 Pa. Calculate the heat absorbed by the gas in the process.

Answer :


Constant pressure p=1.0×105 Pa

Change in volume ΔV=(200-100)×10-6m3=10-4m3

Internal energy U= 1.5pV

So, change in internal energy ΔU=1.5pΔV



We know that work done by the gas is given as


From first law of thermodynamics, we know that,


Where ΔQ=heat supplied to the system

ΔU=change in internal energy

ΔW=work done by the system



heat absorbed by the system=25J.

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