# The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will beA. 60 mB. 71 mC. 100 mD. 141 m

Given in question:

Horizontal range=50m (Assuming it to be R1)

Angle=15° (Assuming it to be θ1)

And we have to find for

Angle =45° (Assuming it to be θ2)

Also velocity is same both cases.

Relation between horizontal range R1 and θ1 is Similarly for range R2 and θ2 it is Dividing both equations, Rate this question :

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