# The horizontal range of a projectile fired at an angle of 15° is 50 m. If it is fired with the same speed at an angle of 45°, its range will beA. 60 mB. 71 mC. 100 mD. 141 m

Given in question:

Horizontal range=50m (Assuming it to be R1)

Angle=15° (Assuming it to be θ1)

And we have to find for

Angle =45° (Assuming it to be θ2)

Also velocity is same both cases.

Relation between horizontal range R1 and θ1 is

Similarly for range R2 and θ2 it is

Dividing both equations,

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