Q. 294.3( 4 Votes )
The heavier block
Answer :
Let the mass of the lighter block be m
Mass of heavier block = 2m
Tension in the string, T = 16 N
Consider the following diagram:
If acceleration produced in the system = a
And acceleration due to gravity, g = 10m/s2
When the system is set into motion,
For the heavier block, 2mg = T + 2ma
For the lighter block, T = mg +ma
After the system is released from rest, change in height of the heavier block in the first second, h = 1/2 at2 (where t=1sec)
⇒ h = 0.5 × g/3 × 12
⇒ h = g/6 m
Decrease in gravitational potential energy corresponding to this =(2m-m) ×g×h
= 19.6 J
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