Q. 125.0( 2 Votes )

The gravitational

Answer :

The radius of first Bohr orbit is given by the relation:

……………(1)


Where ε0 is the absolute permittivity of free space and is given as = 8.854 × 10-12 N-1C2m-2


h is Planck’s constant and is given as 6.64 × 10-34 Js


e is charge on an electron and is equals to 1.6 × 10-19C


me is the mass of an electron, and is equals to 9.1 × 10-31 Kg


mp is the mass of proton and is equals to 1.67 × 10-27 Kg


The forces of coulomb attraction between an electron and proton is given by the relation:


Gravitational forces of attraction between an electron and proton is given by the relation



Where G is the Gravitational constant and is equal to G = 6.67 × 10-11 N m2 Kg2


When coulomb force and Gravitational forces of attraction are equal



Or
…………(1)


Substituting the values of equation (1) in equation (2), we get



Substituting the values, we get



On calculating, we get


r1= 1.21 × 1029 m


Since Universe is 150billion light years wide, which concludes that the radius of first Bohr orbit is much greater than the size of the universe.


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