Answer :

Given that the velocity of m=2kg block on reaching the 4kg block before collision is 1 m/s,

The velocity of M=4kg block is u2= o.

The friction coefficient between the horizontal surface and each of the blocks is .

Distance between the blocks is s=16 m.

From work energy principle

Since it is a perfectly elastic collision

Let v1 and v2 are the velocities after collision of block 2kg and 4kg respectively.

By law of conservation of momentum

______ (1)


_______ (2)

Subtracting equation (2) from (1)


Putting work energy principle for 2kg block when comes to rest

Whereare distances travelled by respective blocks.

Putting work energy principle for 4kg block when comes to rest

So, total distance between 2kg and 4kg block is s

Thus, the separation between the two blocks when they come to rest is 5 cm.

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