Answer :

We know that energy E of a hydrogen or hydrogen-like species is given by,



Now, for the ground state energy of hydrogen(Z=1), Z/n= 1. Thus, E=-13.6 eV.


Also, for the first excited energy of helium ion(Z=2), Z/n= 1. Thus, E=-13.6 eV.


Thus, we have seen that in all hydrogen like species where Z=n, E=-13.6 eV.


So, for the second excited state of lithium ion(Z=2), for the third excited state of beryllium ion(Z=3), so on, we have E=-13.6 eV.


Hence, there will always be an energy level of an hydrogen like species which will be same as the ground state energy of hydrogen.


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