Q. 204.2( 30 Votes )

The equilibrium c

Answer :

Using,

∆G = -RTlnK


∆G = -2.303RTlogK


∆G = change in Gibbs energy


R = 8.314 × 10-3 kJ mol-1 K-1 - constant


T = temperature; given as 300K


K = equilibrium constant


Substituting the above values


∆G = -2.303 × 8.314 × 10-3 × 300 × log 10


∆G = -5.744 kJ mol-1


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