Q. 53.5( 59 Votes )

The enthalpy of c

Answer :


We need to find enthalpy change for reaction

ΔH5 = ΔH(CH4)

ΔH1 = ΔH(CO2) + 2ΔH(H2O) – ΔH(CH4)

ΔH2 = ΔH(CO2)

ΔH4 = 2ΔH(H2O)


ΔH(CH4) = ΔH2 + ΔH4 – ΔH1
So, ΔH= (-393.5-2×285.8+ 890.3)  KJ/mol
= -74.8 KJ/mol

Thus, answer is (i) –74.8 kJ mol–1

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