The electric field intensity produced by the radiations coming from 100 W bulb at a 3 m distance is E. The electric field intensity produced by the radiations coming from 50 W bulb at the same distance is
Power of the bulb P �1 = 100 W
Distance of the bulb from the point of observation = 3 m
Intensity of the radiation from bulb 1, I1 = E
Power of the second bulb P2 = 50 W
We know that, the intensity of radiation is given,
Where W is the energy emitted by the bulb, t is the time, and A is the area on which the radiation is incident. Intensity can also be expressed in terms of power P,
Therefore electric field intensity produced by the 50 W bulb is .
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