Q. 14.2( 11 Votes )

The electric field in a region is given by with E0 = 2.0 × 103 N C–1. Find the flux of this field through a rectangular surface of area 0.2 m2 parallel to the y–z plane.

Answer :


Given:


Electric field :


E0=2.0× 103 N/C


Surface area of plane=0.2m2


The plane is parallel to y-z plane. The normal to this plane is parallel to x-axis. Therefore, area vector for this plane is given by 0.2m2î


ΔS=0.2m2î


We know that,


Flux of electric field through a surface of area ΔS is given by dot product of electric field E with surface area ΔS



Nm2/C


Nm2/C


Nm2/C (putting the value of E0)


Nm2/C


Therefore the flux of this electric field through the given plane surface is 240Nm2/C.



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