Q. 21

The electric field associated with a light wave is given by

E = E0 sin [(1.57 × 107 m–1) (x – ct)].

Find the stopping potential when this light is used in an experiment on photoelectric effect with the emitter having work function 1.9 eV.

Answer :

Given, work function Ф =1.9 eV

…… (1)



On comparing the above two equations, we get


…. (3)


We know that λ=c/f……. (4)


Where λ is the wavelength of light,


C is the speed of the light,


f is the frequency of the light.


From eq (3) & (4)we get the value of frequency



Now, from Einstein’s photoelectric equation


….(5)


Where h is the Planck’s constant,


f is the frequency of light,


e is the charge on an electron ,


is the stopping potential,


Ф is the work function.


Putting the values in eq(5) we have,






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