Q. 37

# The descending pu

The acceleration of the mass if 1 kg is Given

The blocks are of “m” and “M” masses, with radius of r pulley and moment of Inertia “I”

Formula Used

The formula used to find the acceleration of the mass pulled/pushed is determined by the second law of Newton when the Force/Tension applied is equivalent to the product of mass and acceleration where is the force of the mass in terms of tension, is the acceleration and m is the mass of the block.

Explanation

The diagram 10-E7.1 as drawn below shows the tension horizontal as T’ and tension pulling the pulley as T which gives us the diagram as The tension in terms of acceleration due to horizontal tension is  The angular acceleration of the pulley is given as Hence, the torque applied by the pulley due to the mass is given as    Now finding the moment of Inertia we get the value of the mass M as  Putting the value of mass in tension equation, we get the equation of acceleration in terms of tension as Again, putting the value of , we get   Rate this question :

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