The current in a
Ammeter reading of current, i1 in the 1st case=1.75A
Ammeter reading of current, i2 in the 2nd case=2.75A
Voltmeter reading for current i1, V1=14.4V
Voltmeter reading for current i2, V2=22.4V
The ammeter shows the accurate reading while the voltmeter deviate from showing the corresponding potential difference value due to the presence of Zero error, Ve.
Hence the original potential difference can be calculated as, Vo
Where V is the shown voltage in the defected voltmeter.
We also know that the potential difference across the conductor is, V
Where R is the resistance of the conductor
For the 1st and 2nd case, the relation between absolute current and voltage can be written, from eqn.2, as
By dividing these expressions, we get
The terms Vo1 and Vo2 in above equation can be replaced by eqn.1 as
By substituting the given values in the above expression, we get
Hence the zero error associated with the measurement is 0.4V.
Rate this question :
Let there be n rePhysics - Exemplar
Two cells of emfPhysics - Exemplar
Kirchhoff ’s juncPhysics - Exemplar