Answer :

0.4V

Given,


Ammeter reading of current, i1 in the 1st case=1.75A


Ammeter reading of current, i2 in the 2nd case=2.75A


Voltmeter reading for current i1, V1=14.4V


Voltmeter reading for current i2, V2=22.4V


Formula used


The ammeter shows the accurate reading while the voltmeter deviate from showing the corresponding potential difference value due to the presence of Zero error, Ve.


Hence the original potential difference can be calculated as, Vo



Where V is the shown voltage in the defected voltmeter.


We also know that the potential difference across the conductor is, V



Where R is the resistance of the conductor


Solution:


For the 1st and 2nd case, the relation between absolute current and voltage can be written, from eqn.2, as



And



By dividing these expressions, we get



The terms Vo1 and Vo2 in above equation can be replaced by eqn.1 as



By substituting the given values in the above expression, we get



Or,



Or,



Or,



Or,



Hence the zero error associated with the measurement is 0.4V.


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