Q. 15

# The current in a

Answer :

0.4V

Given,

Ammeter reading of current, i_{1} in the 1^{st} case=1.75A

Ammeter reading of current, i_{2} in the 2^{nd} case=2.75A

Voltmeter reading for current i_{1}, *V*_{1}=14.4V

Voltmeter reading for current i_{2}, *V*_{2}=22.4V

Formula used

The ammeter shows the accurate reading while the voltmeter deviate from showing the corresponding potential difference value due to the presence of Zero error, V_{e}.

Hence the original potential difference can be calculated as, V_{o}

Where V is the shown voltage in the defected voltmeter.

We also know that the potential difference across the conductor is, V

Where R is the resistance of the conductor

Solution:

For the 1^{st} and 2^{nd} case, the relation between absolute current and voltage can be written, from eqn.2, as

And

By dividing these expressions, we get

The terms V_{o1} and V_{o2} in above equation can be replaced by eqn.1 as

By substituting the given values in the above expression, we get

Or,

Or,

Or,

Or,

Hence the zero error associated with the measurement is 0.4V.

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