Answer :

We know that,


A= Activity of the substance=1 × 106 s-1

A0 = Initial activity=4 × 106 s-1

t = time=20h

λ = decay constant

So according to the problem,

Now we have to evaluate activity after 100 hours

A = 3.9× 103 disintegrations per second

Hence, the activity after 100 hours is 3.9× 103 disintegrations per second.

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