Answer :


Case-I


Given -


When the supply voltage is 220 V.
Power consumed by the bulb = 100 W
Excess power = 100 − 40 = 60 W



Hence, power converted to light = 60% of 60 W


= 36 W


Case-II


Given


When the supply voltage is 200 V.



Power consumed,


Where


P is the power consumed by the bulb


V is the voltage


Putting the values in the above formula, we get




Excess power


= 82.64 − 40 = 42.64 W



Power converted to light = 60% of 42.64 W = 25.584 W


Percentage drop in the light intensity is-




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