Q. 11

# The coil of an el

Case-I

Given -

When the supply voltage is 220 V.
Power consumed by the bulb = 100 W
Excess power = 100 − 40 = 60 W

Hence, power converted to light = 60% of 60 W

= 36 W

Case-II

Given

When the supply voltage is 200 V.

Power consumed,

Where

P is the power consumed by the bulb

V is the voltage

Putting the values in the above formula, we get

Excess power

= 82.64 − 40 = 42.64 W

Power converted to light = 60% of 42.64 W = 25.584 W

Percentage drop in the light intensity is-

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