Answer :


Coefficient of volume expansion of glycerin, αV = 49 × 10–5 K–1

Rise in temperature, ΔT = 30°C = 30 K

Fractional change in its volume = ΔV/V

We know,


VT2 - VT1 = VT1αVΔT

(m/ρT2)-(m/ρT1) = (m/ρT1VΔT

[(1/ρT2)-(1/ρT1)]/(1/ρT1) = αVΔT

T1 - ρT2)/ρT2 = αVΔT

Where, m is the mass of glycerin

ρT1 is the initial density at T1

ρT2 is the initial density at T2

T1 - ρT2)/ρT2 is the fractional change in density

So, fractional change in density of glycerine = 49 × 10–5 K–1 × 30 K

= 1.47 × 10-2

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses

Calculate the strPhysics - Exemplar

We would like to Physics - Exemplar

<span lang="EN-USPhysics - Exemplar

We would liPhysics - Exemplar

A thin rod havingPhysics - Exemplar

Answer the followNCERT - Physics Part-II

A brass rod of leNCERT - Physics Part-II

A steel tape 1m lNCERT - Physics Part-II

Two ideal gas theNCERT - Physics Part-II

Answer the followNCERT - Physics Part-II