The base of an equilateral triangle with side 2a lies along the y-axis such that the midpoint of the base is at the origin. Find the vertices of triangle.
A.T.Q., two triangles Δ ABC and Δ A’BC are possible.
Given BC = 2a and mid-point of BC is at 0.
⇒ OB = OC = a
i.e., co-ordinate of B and C are (0,a) and (0,-a), respectively.
As triangles are equilateral, we have on Δ ABC
AB = BC = CA = 2a
Applying Pythagoras theorem
Similarly OA’ =
As A and A’ lie on X-axis, coordinates of A and A’ are (, 0) and (-, 0) respectively.
Δ ABC = (0, a), (0, -a), (, 0)
Δ A’BC = (0, a), (0, -a), (-, 0)
Rate this question :