Q. 324.0( 5 Votes )

# The Balmer series in the hydrogen spectrum corresponds to the transition from n_{1} = 2 to n_{2} = 3,4,.......... This series lies in the visible region. Calculate the wavenumber of the line associated with the transition in Balmer series when the electron moves to n = 4 orbit. (R_{H}= 109677 cm^{-1})

Answer :

o According to Bohr’s model for the hydrogen atom

_{H}**cm ^{-1}**

here, n_{1} = 2 and n_{2} = 4 and ** _{H}** = Rydberg’s constant = 109677

Hence, wave number ** ^{-}v**= 109677 ( )

Rate this question :

How useful is this solution?

We strive to provide quality solutions. Please rate us to serve you better.

PREVIOUSThe electronic configuration of the valence shell of Cu is 3d104s1 and not 3d94s2. How is this configuration explained?NEXTAccording to de Broglie, the matter should exhibit dual behaviour, that is both particle and wave-like properties. However, a cricket ball of mass 100 g does not move like a wave when it is thrown by a bowler at a speed of 100 km/h. Calculate the wavelength of the ball and explain why it does not show wave nature.

Related Videos

Structure of Atom - 0757 mins

Structure of Atom - 0666 mins

Structure of Atom - 0366 mins

Structure of Atom - 0558 mins

Structure of Atom - 0461 mins

Structure of Atom - 0868 mins

Understand photoelectric effect42 mins

Structure of Atom - 0165 mins

Structure of Atom - 0262 mins

Quiz on wave mechanical model of atom40 mins

Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Expertsview all courses

Dedicated counsellor for each student

24X7 Doubt Resolution

Daily Report Card

Detailed Performance Evaluation