Answer :
We know that kinetic energy of ideal gas is given by
…. (I)
Where K. E=kinetic energy of gas
kB = Boltzmann constant=1.38 × 10–23 J K–1.
T = temperature of gas
In kinetic theory of ideal gas, molecule of gas is moving in straight line.
Hence, they will only have translational kinetic energy.
Given
K. E=0.040 eV
We know that
1 eV = 1.6 × 10–19J
0.040eV=0.040
J
From equation (I) we can write
Therefore, the temperature of gas is 309.2K.
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