Answer :

We know that kinetic energy of ideal gas is given by


…. (I)


Where K. E=kinetic energy of gas


kB = Boltzmann constant=1.38 × 10–23 J K–1.


T = temperature of gas


In kinetic theory of ideal gas, molecule of gas is moving in straight line.


Hence, they will only have translational kinetic energy.


Given


K. E=0.040 eV


We know that


1 eV = 1.6 × 10–19J


0.040eV=0.040J


From equation (I) we can write




Therefore, the temperature of gas is 309.2K.


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