Q. 345.0( 2 Votes )

The area of the quadrilateral ABCD, where A(0,4,1), B (2, 3, –1), C(4, 5, 0)and D (2, 6, 2), is equal to
A. 9 sq. units

B. 18 sq. units

C. 27 sq. units

D. 81 sq. Units

Answer :

Given,


A(0,4,1), B (2, 3, –1), C(4, 5, 0) and D (2, 6, 2), therefore






Since, opposite vectors of this parallelogram are equal and opposite, therefore ABCD is a parallelogram and we know area of a parallelogram ABCD is


|AB × CD|






= 9 sq units

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