Q. 74.1( 18 Votes )

The amplitude of the magnetic field part of a harmonic electromagnetic wave in vacuum is B0 = 510 nT. What is the amplitude of the electric field part of the wave?

Answer :

Given: Amplitude of magnetic field part of harmonic electromagnetic wave, B0 = 510 nT

Converting into Tesla, B0 = 510 × 10-9 T


Speed of light in vacuum, c = 3 × 108 m/s


Amplitude of the electric field part of the wave can be calculated by the following expression:


E = c B0


E = 3× 108ms-1 ×510 × 10-9 T


E = 153 N/C


Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Source of Electromagnetic waveSource of Electromagnetic waveSource of Electromagnetic wave6 mins
Back to 11th | Interactive Quiz: Waves (part-2)Back to 11th | Interactive Quiz: Waves (part-2)Back to 11th | Interactive Quiz: Waves (part-2)52 mins
Electromagnetic InductionElectromagnetic InductionElectromagnetic Induction50 mins
Back to 11th | Interactive Quiz: Waves (part-1)Back to 11th | Interactive Quiz: Waves (part-1)Back to 11th | Interactive Quiz: Waves (part-1)49 mins
S.H.M.S.H.M.S.H.M.51 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

Speed of electromagnetic waves is the same

HC Verma - Concepts of Physics Part 2

An electric field and a magnetic field exist in a region. The fields are not perpendicular to each other.

HC Verma - Concepts of Physics Part 2