# The activation energy for the reaction 2 HI(g) → H2 + I2 (g) is 209.5 kJ mol–1 at 581K.Calculate the fraction of molecules of reactants having energy equal to or greater than activation energy?

Given-

Energy of activation, Ea= 209.5 kJ mol1

Ea in joules = 209.5 × 1000 = 209500 J mol1

Temperature, T = 581K

Gas constant, R = 8.314 J K-1 mol-1

Using Arrhenius equation,

k = A

In this equation, the term represents the number of molecules which have kinetic energy greater than the activation energy, Ea.

The number of molecules = Equation 1

Substituting all the known values in equation 1, we get,

= e-43.3708

Finding the value of anti ln(43.3708), we get, 1.47 × 10-19

The fraction of molecules of reactants having energy equal to or greater than activation energy is 1.47 × 10-19

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Interactive Quiz on Integrated Rate equation58 mins
Interactive quiz on arrhenius equation53 mins
Arrhenius equation & Collision Theory59 mins
Integrated Rate Equation52 mins
Questions based on Chemical Reaction57 mins
Factors influencing Rate of Chemical Reaction45 mins
Questions Based on Factors influencing Rate of Chemical Reaction41 mins
Learn Rate of a Chemical Reaction65 mins
15 Concept Builder Questions of Chemical Bonding - Reminding 11th46 mins
Full Chapter Quiz | Solid State | Check your learning43 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses