Answer :

From the fig. the capacitors 4μF and 8μF are in series.

Capacitors 3μF and 6μF are in series

C_{1} and C_{2} are in parallel combination

Two rows are in parallel. So the voltage across each row is the same, and that is equal to 50V.

The charge on the branch ACB is

Charge on the branch ADB is

*Q _{ADB}*

Voltage,

Where

Q is the charge on the capacitor

C is the capacitance of the capacitor

The voltage at 4μF is =

The voltage at 8μF is =

Voltage at node C is =V

The voltage at 3μF is

The voltage at 6μF is

The voltage at node

b) if a capacitor is connected between node C and D. if we redraw the circuit, it will look like. Here bridge is balanced at the condition

the charge on the capacitor will be zero.

Because the bridge is balanced so the potential difference between C and D will be zero. So no charge flow will occur.

The voltage at node C and node D is same and is equal to

If a capacitor is connected between node C and D, the charge flow will be zero.

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