Answer :

Note: If a conducting uncharged material is brought in contact with a charged surface then the charges are shared uniformly between the two bodies.


Given: Charge on sphere 1, q1 = 6.5 × 10-7 C


Charge on sphere 2, q2 = 6.5 × 10-7 C


Charge on sphere 3, q3 = 0



Step 1: The uncharged sphere is brought in contact with sphere 1. Since sphere 1 has charge ‘q’, it gets distributed among sphere 1 and sphere 3.


Now, charge on sphere 1 = q/2


Charge on sphere 2 = q/2


At this point the sphere 3 which was initially uncharged has a charge “q/2”.


Step 2: Now sphere 3 is brought in contact with sphere 2 due to which 1/4 × q will flow from sphere 2 to sphere 3. Now sphere 2 and sphere 3 have “3/4 × q” charge.


Now, q1 = 1/2 × 6.5 × 10-7 C


3.25 × 10-7 C


q2 = 3/4 × 6.5 × 10-7 C


4.87 × 10-7 C


q3 = 3/4 × 6.5 × 10-7 C


4.87 × 10-7 C


We know that,


…(1)


Where, F= mutual force of attraction


q1 = charge on sphere 1


q2 = charge on sphere 2


r = distance between centres



Where, ε0 is the permittivity of the free space.


Plugging the values of q1, q2 and r in equation (1), we get



F = 5.703 × 10-3 N


The repulsive force between sphere 1 and sphere 2 is 5.703 × 10-3 N.


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