Q. 314.9( 7 Votes )

Suppose India had

Answer :

By 2020 India need 2,00,000 MW of electric energy per year, out of which 10% of energy is to be obtained from nuclear power plants.


Thus, Nuclear power plants should produce,



= 20,000×106×365×24×60×60 J


= 6.3072×1017 J of energy


Given that Fission of one releases 200 MeV of energy.


200 MeV = 200×106×1.6×10-19 J = 3.2×10-11 J


Since, reactor is 25% efficient, total energy produced per atom,


Ea = 0.25×3.2×10-11 J = 8×10-12 J


Number of atoms to be fission to produce required energy,



We know that, 235 g Uranium contains 6.023×1023 atoms.


Thus, for 7.884×1028 atoms we need,



Hence, India need 3.076×104 Kg of uranium in 2020 to produce sufficient electricity.


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