By 2020 India need 2,00,000 MW of electric energy per year, out of which 10% of energy is to be obtained from nuclear power plants.
Thus, Nuclear power plants should produce,
= 20,000×106×365×24×60×60 J
= 6.3072×1017 J of energy
Given that Fission of one releases 200 MeV of energy.
200 MeV = 200×106×1.6×10-19 J = 3.2×10-11 J
Since, reactor is 25% efficient, total energy produced per atom,
Ea = 0.25×3.2×10-11 J = 8×10-12 J
∴ Number of atoms to be fission to produce required energy,
We know that, 235 g Uranium contains 6.023×1023 atoms.
Thus, for 7.884×1028 atoms we need,
Hence, India need 3.076×104 Kg of uranium in 2020 to produce sufficient electricity.
Rate this question :
Four nuclei of anPhysics - Board Papers
Calculate the Q-vHC Verma - Concepts of Physics Part 2
If three helium nHC Verma - Concepts of Physics Part 2
Typically, in a fHC Verma - Concepts of Physics Part 2
32P beHC Verma - Concepts of Physics Part 2
Find the energy lHC Verma - Concepts of Physics Part 2
Two lithium nucleHC Verma - Concepts of Physics Part 2
Fusion processes,Physics - Exemplar