Q. 323.8( 4 Votes )

Study the following cross and showing self-pollination in F1, fill in the blank and answer the question that follows:


In the above cross what are the combinations of character in the F2 progeny? What are their ratios?

Answer :

Here the parents are dihybrid in nature as dihybrids are two individuals differing in two different contrasting pairs of characters. In the given example the parents are differing in two characters, i.e., shape (round and wrinkled) and color (yellow and green). A cross between two pure-breeding dominant and recessive parents gives heterozygous dominant offspring. All F1 progeny in this cross will have genotype RrYy and will exhibit round and yellow phenotype. Self cross in F1 progeny gives F2 generation and follow law of independent assortment of characters.


So,


F1 – Rr Yy X Rr Yy


Round, yellow Round, yellow

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