Q. 105.0( 3 Votes )

State and prove t

Answer :

Consider a body m lying at a position A at a height h, above the ground. As the body falls, its kinetic energy increases at the expense of its potential energy.

At point A

The body is at rest

The kinetic energy of a body at A = KA

The potential energy of body at A = UA

The total techanical energy of body at A = EA

At point B

Suppose the body falls through a distance x and reaches B with velocity v. Then

u = 0

s = x

a = g

The kinetic energy of body at B = KB

The potential energy of a body at B = UB

The total energy of the body at B = EB

At point C

Suppose the body reaches C (on the ground) with velocity v’. Then considering motion from A to C

u = 0

s = h

a = g

v = v’

Kinetic energy of body at C = KC

Potential energy of body at C = UC

Total mechanical energy of body at C = EC

As a body falls freely under gravity P.E. decreases and K.E increases by equal amounts, however the, total mechanical energy remains constant.

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