Q. 9 B3.7( 65 Votes )

# Solve the followi

Given:

Effective resistance when two resistors are connected in series =80 Ω

Let us consider the resistances as R1 and Rin series  combination,

V   =   V1    +    V2    and V=IR

As we know that in series connection current is constant, we get

R= R1  +  R2  =  80  Ω ---(1)

Effective resistance when two resistors are connected in parallel combination = 20Ω

We get

........(2)

putting the value of equation(1) in equation(2)

R1R2 = 1600

(R1-R2)2 = (R1 + R2)2 - 4R1R2

= 802 - (4×1600)

= 0

R1-R2 = 0 ---(3)

R1=40

Subtracting (1) and(3)

R2
=40Ω

we get R1 = R2 = 40Ω

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