RD Sharma Class 10 Chapter 6 (Trigonometric Identities) Solutions
ShareChapter-6 of RD Sharma Class 10 textbook requires you to have prior knowledge of trigonometric ratios. You can obtain the first trigonometric identity by considering the right-angled triangle, applying the Pythagoras theorem, and using the hit and trial.
The first identity is (sin2A + cos2A = 1); use this identity to obtain other useful trigonometric identities. The first exercise includes questions in which you need to prove both sides of an equation equal. In the second exercise, there are questions that involve the use of Pythagoras theorem and trigonometric ratios.
Chapter 6 - Trigonometric Identities
Class 10th|RD Sharma - MathematicsChapter 6 - Trigonometric Identities
RD Sharma - MathematicsClass 10th , RD Sharma
| Chapter 1 - Real Numbers |
| Chapter 2 - Polynomials |
| Chapter 3 - Pair of Linear Equations in Two Variables |
| Chapter 4 - Triangles |
| Chapter 5 - Trigonometric Ratios |
| Chapter 6 - Trigonometric Identities |
| Chapter 7 - Statistics |
| Chapter 8 - Quadratic Equations |
| Chapter 9 - Arithmetic Progressions |
| Chapter 10 - Circles |
| Chapter 11 - Constructions |
| Chapter 12 - Some Application of Trigonometry |
| Chapter 13 - Probability |
| Chapter 14 - Co-ordinate Geometry |
| Chapter 15 - Areas Related to Circles |
| Chapter 16 - Surface Areas and Volumes |
More books in your class
Class 10th RD SharmaMore Reference Books
Class 10thImportant Trigonometric Identities for Class 10
- sin (90° - A) = cos A
- cos (90° - A) = sin A
- tan (90° - A) = cot A
- cot (90° - A) = tan A
- sec (90° – A) = cosec A
- cosec (90° – A) = sec A
- sin2A + cos2A = 1
- sec2A - tan2A = 1, when 0° ≤ A < 90°
- cosec2A = 1 + cot2A, when 0° < A ≤ 90º
Concepts in RD Sharma Class 10 Chapter-6
The entire chapter is based on the use of identities. By deriving each identity, you will get into the depth of every formula and implement them effectively. For proving both sides of the equation equal, you must consider working out with each term of the complex side.
Further, there are questions in which you will be provided with a condition. Using the given condition, you need to prove the left and right-hand side of the equation equal. Consider cross-checking your answers by taking a quick look at Chapter-6 Solutions of RD Sharma Class 10.
