RD Sharma Class 10 Chapter 5 (Trigonometric Ratios) Solutions

Having studied the core concepts of trigonometry from NCERT, including trigonometric ratios and identities, you can enhance your question-solving ability by solving RD Sharma Class 10 Chapter-5 questions. To begin with, the first exercise contains questions asking you to find the values of trigonometric ratios. 

In the second exercise, you will come across questions that require you to obtain the result by putting the correct value of trigonometric ratios. The third exercise is a mix of questions that require you to evaluate the trigonometric expressions and prove both sides of an equation equal. 

Trigonometric Ratios | RD Sharma Class 10 Chapter-5

In a right-angled triangle ABC, where the measure of angle B is 90°, you can obtain the measure of an angle, say A using

• sin A = Side opposite to angle A/ hypotenuse
• cos A = Side adjacent to angle A/ hypotenuse
• tan A = Side opposite to angle A/ side adjacent to angle A
• cosec A = 1/ sin A
• sec A = 1/ cos A
• tan A = 1/ cot A
• tan A = sin A/ cos A

Concepts in RD Sharma Class 10 Chapter-5

To master this chapter, you have to first learn the trigonometric ratios of angle A in right-angled triangle ABC. For finding the third side of a right-angled triangle when two sides are known, Pythagoras theorem will come into use. 

You should know how to derive the trigonometric ratios of 0°, 30°, 45°, 60° and 90°. If you are not able to derive the ratios, then you can learn the value of angle A at different angles. This chapter also consists of questions that require you to prove the left and right-hand side of an equation equal. In case you have doubts, you can take reference from RD Sharma Class 10 Chapter-5 Solutions.

Following are the concepts of Chapter-5 Trigonometric Ratios.

1. Introduction
2. Trigonometric Ratios
3. Trigonometric Ratios of Some Specific Angles
4. Trigonometric Ratios of Complementary Angles