Q. 14
Rate law for the reaction A + 2B → C is found to be
Rate = k [A][B]
Concentration of reactant ‘B’ is doubled, keeping the concentration of ‘A’ constant, the value of rate constant will be______.
A. the same
B. doubled
C. quadrupled
D. halved
Answer :
Given,
RateO = k[A][B], the rate is directly proportional to the unit power of the concentration of element B. So, if its concentration is doubled the rate of reaction is also doubled.
Rate=k[A][2B] 2K[A][B]
2Rate0
Thus Option (ii) is correct.
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