Q. 14

Rate law for the reaction A + 2B C is found to be

Rate = k [A][B]

Concentration of reactant ‘B’ is doubled, keeping the concentration of ‘A’ constant, the value of rate constant will be______.

A. the same

B. doubled

C. quadrupled

D. halved

Answer :

Given,

RateO = k[A][B], the rate is directly proportional to the unit power of the concentration of element B. So, if its concentration is doubled the rate of reaction is also doubled.


Rate=k[A][2B] 2K[A][B] 2Rate0


Thus Option (ii) is correct.

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