Answer :



Part I :




Square term is always positive and (x + 1)2 ≠ 0. So, x > 0 and x ≠ -1


Part II :




Square term is always positive and (x – 1)2 ≠ 0. So, x < 0 and x ≠ 1


So, by taking union of part I and part II we have final solution i.e., x R – {-1, 0, 1}


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