Q. 95.0( 2 Votes )

The mid-value of a class interval is 42 and the class size is 10. The lower and upper limits are
A. 37-47

B. 37.5-47.5

C. 36.5-47.5

D. 36.5-46.5

Answer :

Given,


Mid value of class interval = 42


Class size = 10


Let the upper limit of class = u


Let lower limit of class = l


We know that,


Mild value = 1/2 (u + l)


42 = 1/2 (u + l)


= u + l = 84..............(i)


Class size = u – l


= u – l = 10 (given)


Adding equation (ii) & equation (i), we get,


2u = 94


u = 94/2 = 47.


From equation (ii)


u – l = 10


l = 47 – 10 = 37.

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