# The graph of the linear equation 4x + 3y = 12 cuts the x-axis at the pointA. (4, 0)B. (0, 4)C. (0, 3)D. (3, 0)

4x + 3y = 12

3y = 12 – 4x

When x = 0, then,

When x = 3, then,

y = 0

Thus, we have the following table,

Plotting these points we have the following graph,

The blue line in the graph is the required line of the equation, 4x + 3y = 12

According to the graph, the equation,

4x + 3y = 12 cuts the x-axis at the point (3, 0)

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