# The angle of depression of a car parked on the road from the top of a 150-m-high tower is 30°. The distance of the car from the tower isA. 50√3 mB. 150√3mC.150√2 mD. 75 m

In the figure, AB is the tower and car is at the point C. Join A and B to C. So we get a right-angled triangle ABC with right angle at B. Also height of the tower is 150 m. So, AB = 150 m. Again, draw a line AD parallel to BC. The angle of depression of the car from the top of AB is 30°. So, DAC = ACB = 30°. We have to find the distance of the car from the tower, that is BC. For this, we will use the trigonometric ratio tan in ∆ABC.

So from ∆ABC,

or,

So, the correct option is (B).

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Heights and Distances33 mins
Quiz | Imp. Qs. on Heights and Distances37 mins
NCERT | Basics of Heights and Distances37 mins
Idioms and Phrases43 mins
Goprep Genius Quiz | Analogy and Classification48 mins
Acid - Types and Nomenclature52 mins
Agriculture and its Importance35 mins
Foundation | Permutation and Combination45 mins
Goprep Genius Quiz | Direction and Distance58 mins
Light and it's Reflection58 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses