Q. 94.7( 3 Votes )

The angle of depression of a car parked on the road from the top of a 150-m-high tower is 30°. The distance of the car from the tower is
A. 50√3 m

B. 150√3m

C.150√2 m

D. 75 m

Answer :

Untitled43.jpg


In the figure, AB is the tower and car is at the point C. Join A and B to C. So we get a right-angled triangle ABC with right angle at B. Also height of the tower is 150 m. So, AB = 150 m. Again, draw a line AD parallel to BC. The angle of depression of the car from the top of AB is 30°. So, DAC = ACB = 30°. We have to find the distance of the car from the tower, that is BC. For this, we will use the trigonometric ratio tan in ∆ABC.


So from ∆ABC,



or,



So, the correct option is (B).

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