Q. 95.0( 1 Vote )

Mark the correct

Since, y = x – 3;

Therefore, for x = 11, y = 8.

For x = 12, y = 9.[ But the value y = 9 does not exist in the given set.]

For x = 13, y =10.

So, we have R = {(11, 8), (13, 10)}

Now, R1 = {(8, 11), (10, 13)}.

Therefore, option A is correct.

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