Answer :
In Δ ABC and Δ FED
AB = FE [sides of hexagon]
BC = ED [sides of hexagon]
∠ ABC = ∠ FED = 120°
∴ Δ ABC ≅ Δ FED
AC = FD [CPCT]
In Δ ABC
∠ BAC = ∠ BCA [angle made on opposite sides]
∠ BAC + ∠ BCA + ∠ ABC = 180°
2∠ BCA + 120° = 180°
⇒ 2 ∠ BCA = 180° - 120°
⇒ 2∠ BCA = 60°
⇒
∴ ∠ BCA = ∠ BAC = 30°
Similarly, ∠ EFD = ∠ EDF = 30°
∠ BCD = ∠ BCA + ∠ ACD
⇒ 120° = 30° + ∠ ACD
⇒ ∠ ACD = 120° - 30°
⇒ ∠ ACD = 90°
∠ EDC = ∠ FDE + ∠ FDC
⇒ 120° = 30° + ∠ FDC
⇒ ∠ FDC = 120° - 30°
⇒ ∠ FDC = 90°
∴ From above calculations AC = FD and AF = CD and ∠ FDC = ∠ ACD = 90°
∴ ACDF is a rectangle.
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