Q. 94.4( 5 Votes )

<span lang="EN-US

Answer :

In Δ ABC and Δ FED

AB = FE [sides of hexagon]


BC = ED [sides of hexagon]


ABC = FED = 120°


Δ ABC Δ FED


AC = FD [CPCT]


In Δ ABC


BAC = BCA [angle made on opposite sides]


BAC + BCA + ABC = 180°


2 BCA + 120° = 180°


2 BCA = 180° - 120°


2 BCA = 60°



BCA = BAC = 30°


Similarly, EFD = EDF = 30°


BCD = BCA + ACD


120° = 30° + ACD


ACD = 120° - 30°


ACD = 90°


EDC = FDE + FDC


120° = 30° + FDC


FDC = 120° - 30°


FDC = 90°


From above calculations AC = FD and AF = CD and FDC = ACD = 90°


ACDF is a rectangle.






Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Related Videos
Champ Quiz | Polygons (Quadrilaterals)Champ Quiz | Polygons (Quadrilaterals)Champ Quiz | Polygons (Quadrilaterals)30 mins
Understanding QuadrilateralUnderstanding QuadrilateralUnderstanding Quadrilateral40 mins
RD Sharma | Understanding Shapes (Polygons) Part 1RD Sharma | Understanding Shapes (Polygons) Part 1RD Sharma | Understanding Shapes (Polygons) Part 142 mins
Basic Understanding of PolygonsBasic Understanding of PolygonsBasic Understanding of Polygons44 mins
Area of PolygonsArea of PolygonsArea of Polygons41 mins
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
caricature
view all courses
RELATED QUESTIONS :

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

<span lang="EN-USKerala Board Mathematics Part I

In a regulaKerala Board Mathematics Part II