Q. 94.6( 5 Votes )

In Figure 3, a ri

Answer :

Given,


A right-angled triangle ABC,


AB = 8 cm


BC = 6 cm


Let’s suppose Triangle ABC is right angled such that;


B = 90°


O be the center and


r be the radius of the incircle.


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AB is a tangent to the circle at point P


BC is a tangent to the circle at point N and


CA is a tangent to the circle at point M


OP = ON = OM = r (radius of the circle)


Area of ∆ABC = 1/2 ×BC×AB = 24 cm2


By Pythagoras theorem;


CA2 = AB2 + BC2


CA2 = (8)2 + (6)2


CA2 = 100 cm


CA = 10 cm


Area of ∆ABC = Area of ∆OAB + Area of ∆OBC + Area of ∆OCA






r = 2 cm


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