Q. 94.0( 4 Votes )

In Δ ABC, if A = 100° AD bisects A and ADBC. Then, B =
A. 50°

B. 90°

C. 40°

D. 100°

Answer :

Given,

AD perpendicular to BC


A = 100o


In ,


ADB + B + DAC = 180o


90o + B + A = 180o


B + * 100o = 180o – 90o


B + 50o = 90o


B = 40o

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