Q. 9

In Δ ABC

Class 9th RD Sharma - Mathematics 9. Triangle and Its Angles

Answer :

Given,

AD perpendicular to BC

∠A = 100^o

In ,

∠ADB + ∠B + ∠DAC = 180^o

90^o + ∠B + ∠A = 180^o

∠B + * 100^o = 180^o – 90^o

∠B + 50^o = 90^o

∠B = 40^o

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