Q. 94.5( 12 Votes )

# In a rhombu

Answer :

To Find: ADB

Given: ABCD is a rhombus and ACB = 40˚

Concept Used:

Diagonals of a rhombus bisect at the right angle.

Sum of angles of a triangle = 180˚

SAS Congruence: If two sides and one angle of a triangle is equal to two sides and angle of another triangle then the two triangles are said to be congruent.

Diagram:

Explanation:

BOC = 90˚

In Δ BOC,

BOC + ACB + CBD = 180˚

90˚ + 40˚ + CBD = 180˚

CBD = 180˚ - 30˚

CBD = 50˚

Now,

In Δ BOC and Δ AOD, we get,

AD = BC [All sides of rhombus are equal]

AO = OC [ Diagonals of a rhombus bisect each other]

OD = OB [Diagonals of a rhombus bisect each other]

Therefore,

Δ BOC and Δ AOD are congruent by SAS congruence.

Now,

ADB = 50˚ [By C.P.C.T]

Hence, ADB = 50˚.

Rate this question :

How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
view all courses
RELATED QUESTIONS :

The figure formedRS Aggarwal & V Aggarwal - Mathematics

A <imRS Aggarwal & V Aggarwal - Mathematics

In a parallelpgraRD Sharma - Mathematics