Q. 94.0( 4 Votes )

If (x-1) i A. f (x) g(x)

B. -f(x)+g(x)

C. f(x)-g(x)

D. {f(x)+g(x)}g(x)

Answer :

Given,

(x-1) is a factor of f (x) but not of g(x).


Therefore, x-1 is also a factor of f(x) g(x).

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