Q. 94.0( 4 Votes )
If (x-1) i A. f (x) g(x)
B. -f(x)+g(x)
C. f(x)-g(x)
D. {f(x)+g(x)}g(x)
Answer :
Given,
(x-1) is a factor of f (x) but not of g(x).
Therefore, x-1 is also a factor of f(x) g(x).
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