Answer :
In ΔPAO
tan30° = AO/PA
1/√3 = 3/PA
PA = 3√3 cm
OR
In ΔOPQ
P + Q + O = 180°
2Q + P = 180°
2Q + 90°= 180° (Radius is perpendicular to tangent at point of contact)
2Q = 90°
Q = 45°
Rate this question :
How useful is this solution?
We strive to provide quality solutions. Please rate us to serve you better.
Try our Mini CourseMaster Important Topics in 7 DaysLearn from IITians, NITians, Doctors & Academic Experts
view all courses
Dedicated counsellor for each student
24X7 Doubt Resolution
Daily Report Card
Detailed Performance Evaluation
