Q. 94.2( 44 Votes )
If the 9th term of an A.P. is zero then show that the 29th term is twice the 19th term.
Answer :
Now, By using nth term of an A.P. formula
tn = a + (n – 1)d
where n = no. of terms
a = first term
d = common difference
tn = nth terms
Given: t9 = 0
⇒ t9 = a + (9 – 1)d
⇒ 0 = a + 8d
⇒ a = – 8d
To Show: t29 = 2× t19
Now,
⇒ t29 = a + (29 – 1)d
⇒ t29 = a + 28d
⇒ t29 = – 8d + 28d = 20 d (since, a = – 8d )
⇒ t29 = 20 d
⇒ t29 = 2 × 10 d ….(1)
Also,
⇒ t19 = a + (19 – 1)d
⇒ t19 = a + 18d
⇒ t19 = – 8d + 18d = 10 d (since, a = – 8d )
⇒ t19 = 10 d …..(2)
From eq. (1) and eq. (2) we get,
t29 = 2× t19
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